# Kw/Day Calculations

### #1

Posted 29 March 2006 - 12:52 PM

I have one question and I hope that you can help me! In My site I have 4 KV Motor with 650HP and 0.92 Power Factor, and I want to calculate the Kw/Day for the motor but I don’t have the formula to calculate KW/Day. And another question that is the power rating which is written on the name plate (650HP) is it the same (650 HP/Hr)? And if not, what is the formula to find the HP/Hr from the rated power on the name plate?

I Hope that you will answers my doubts.

Many Thanks,

Mohammad Tahseen

### #2

Posted 29 March 2006 - 06:38 PM

The rated power of the motor (KW or HP) is the rated output power of that motor. When the motor is operating at full load, it should be producing that nameplate power out the motor shaft.

The electrical input power will be higher because it will also include the losses in the motor.

If we assume that the motor has an efficiency of say 92%, then the input power will be the output power divided by the efficiency.

In order to calculate the KW/Hr used by the motor, you need to know the power consumed by the motor and this is dependant on the shaft power that the motor is producing. In otherwords, it is very load dependant. There is no magic formula that will give you this information unless you know what the output power is.

If we assume that the motor operates continuously at rated shaft power, then the KWHrs used would be 650 x 0.746 KW / efficiency x number of hours run. Note this assumes continuous operation at full load. This is very rarely the case!! At half load, the KWHrs will be almost halved.

Best regards,

Mark Empson | administrator

Skype Contact = markempson | phone +64 274 363 067

LMPForum | Power Factor | L M Photonics Ltd | Empson family | Advanced Motor Control Ltd | Pressure Transducers | Smart Relay | GSM Control | Mark Empson Website | AuCom | Soft Starters

### #3

Posted 30 March 2006 - 06:15 AM

So if I have continuous reading of the current as a feed back to PLC system and already my voltage is fixed to around 4.0KV and I Know the power factor, Can I take one calculation each one minute (or less) for the power (sqr3*I*V*P.F) for one hour and find the average and consider it as Kw/hr then multiply this with working hours for one day to find Kw/Day??

Many Thanks and Best Regards

### #4

Posted 30 March 2006 - 10:11 AM

Yes, if you measure the input power, you can integrate this over the period of use to determine the KWHrs consumed.

Best regards,

Mark Empson | administrator

Skype Contact = markempson | phone +64 274 363 067

LMPForum | Power Factor | L M Photonics Ltd | Empson family | Advanced Motor Control Ltd | Pressure Transducers | Smart Relay | GSM Control | Mark Empson Website | AuCom | Soft Starters

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