# Power Factor Correction

### #1 AB2005

AB2005

Senior Member

• Full Member
• 411 posts
• Gender:Male

Posted 22 October 2006 - 03:32 AM

Dear All,

We have a large number of Fluorescent and mercury lamps in our plant. I want to connect the PFC capacitor at each lamp for reducing the line losses. Please check my calculations for single phase capacitor and guide to me if you found any mistake.

QC=Px(tanΦ1-tanΦ2)

QC=V²xWxC

C=QC/V²xW

For example, Fluorescent lamp = 40W, 220V, 50HZ and cosΦ 0.45. I want to improve the power factor at 0.96. So,

QC=40x(1.98-0.29)

QC=67.6VAR

C=67.6/220x220x(2x3.14x50)

C=4.4uf

Is it correct?

"Don't assume any thing, always check/ask and clear yourself".

### #2 AB2005

AB2005

Senior Member

• Full Member
• 411 posts
• Gender:Male

Posted 02 November 2006 - 02:32 AM

Any one can provide me any link, or any help? I am confused what to do.

"Don't assume any thing, always check/ask and clear yourself".

#### 0 user(s) are reading this topic

0 members, 0 guests, 0 anonymous users