
kVAHr Saving
#1
Guest__*
Posted 21 January 2005 - 10:03 AM
kWHr is a part of kVAHr. How can there be no change in kVAHr when there will be change in kWHr, since the PF at Meter end remain constant?
If capacitor bank has to reduce its load, what would be the impact on saving?
Thanks.
#2
Posted 22 January 2005 - 07:35 PM
If you have a motor with a smal load, the change in load will affect the KWHr but have very little impact on the KVAHr. The KVA is the vector sum of the resistive power and the reactive power. If the reactive power is significantly larger than the resistive power, small changes in the resistive power (KW) will not show up in the KVAHr.
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Mark Empson | administrator
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LMPForum | Power Factor | L M Photonics Ltd | Empson family | Advanced Motor Control Ltd | Pressure Transducers | Smart Relay | GSM Control | Mark Empson Website | AuCom | Soft Starters
#3
Guest__*
Posted 12 July 2005 - 07:37 AM
#4
Posted 12 July 2005 - 10:48 AM
Domestic loading is primarly resistive and electronic. There is very little inductive load in the domestic situation so there is no advantage in power factor correction. There is however, a reasonable amount of electronic load which contributes to distortion power factor. It is best to keep quiet about this as we do not want the power companies to add a surcharge for harmonics!!
Best regards,
Mark Empson | administrator
Skype Contact = markempson | phone +64 274 363 067
LMPForum | Power Factor | L M Photonics Ltd | Empson family | Advanced Motor Control Ltd | Pressure Transducers | Smart Relay | GSM Control | Mark Empson Website | AuCom | Soft Starters
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