
Derating Calculation of Capacitor Bank
#1
Guest__*
Posted 22 September 2005 - 03:29 PM
Is it right if I calculate like that 100k x 380 / 440 ?
=86.363kVar ??
Thanks in advance
Stephen
#2
Posted 22 September 2005 - 06:43 PM
The capacitor provides an impedance that is frequency dependant. If you change the frequency, then the impedance changes and this will affect the current. If the frequency does not change, then the impedance is constant and the current will reduce in proportion to the voltage reduction.
As KVAR is a product of both voltage and current, the KVAR wil reduce by the voltage reduction squared.
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#3
Guest__*
Posted 23 September 2005 - 04:07 PM
Thanks. For the above example,
= 100kVar - (440-380) (440-380))
= 100kVar - 3.6kVar
= 96.4kVar
Right?
Stephen
#4
Posted 23 September 2005 - 08:46 PM
Assuming both ratings are at 50Hz,
KVAR = 100 x (380/440) x (380/440)
Best regards,
Mark Empson | administrator
Skype Contact = markempson | phone +64 274 363 067
LMPForum | Power Factor | L M Photonics Ltd | Empson family | Advanced Motor Control Ltd | Pressure Transducers | Smart Relay | GSM Control | Mark Empson Website | AuCom | Soft Starters
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