Relay settings for 15 MVa transformer. |
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Relay settings for 15 MVa transformer. |
Nov 4 2005, 10:03 AM
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#1
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![]() Member ![]() ![]() ![]() ![]() Group: Full Member Posts: 165 Joined: 3-September 04 Member No.: 861 |
WE have a 15 Mva 33/13.8 kv 60 Hz transformer on which the load is 7 Mva.
What should be 50/51 and 50n/51n setting on the secondary side. Overcurrent... ? ( amps) OC Curve..............? ( SIT or definite) Delay...............? mS Earth fault.......... ( Amps) EF Curve................. Delay..................... The load is entirely motors and the biggest motor is 250 HP ( soft start). The primary impedance voltage is 9.06% thanks chaterpilar |
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Nov 5 2005, 10:03 AM
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#2
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![]() Member ![]() ![]() ![]() ![]() Group: Full Member Posts: 165 Joined: 3-September 04 Member No.: 861 |
Marke,
I am waiting for your valuable opinion. regards, Chaterpilar |
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Nov 5 2005, 10:03 AM
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#3
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![]() Member ![]() ![]() ![]() ![]() Group: Full Member Posts: 165 Joined: 3-September 04 Member No.: 861 |
Marke,
I am waiting for your valuable opinion. regards, Chaterpilar |
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Nov 8 2005, 09:13 PM
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#4
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Intermediate Member ![]() ![]() ![]() Group: Members Posts: 30 Joined: 8-November 02 From: Northern Cape, South Africa Member No.: 168 |
chaterpillar:
This is a very difficult question to answer. All your settings would depend on how many levels of protection you have downstream, and how much time you are allowed upstream. It would also be dependant on the kind of relays you are using (electromechanical, electronic, etc) and what kind of protective schemes you are using on the transformer (REF, differential, etc) Normally your residual O/C and E/F curves would be Normal Inverse Curves. You E/F settings would depend on your transformer earthing arrangement. (solidly, high/low resistance, reactance, ungrounded, etc.) Without your total system lay-out it would be impossible to give any setting recommendations. Regards Ralph |
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Nov 9 2005, 02:40 AM
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#5
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![]() Posting Freak ![]() ![]() ![]() ![]() ![]() ![]() Group: Moderator Posts: 654 Joined: 22-February 03 From: USA, California Member No.: 285 |
Marke is in a particularly remote part of the world just now, he does not have regular internet access.
-------------------- "He's not dead, he's just pinin' for the fjords!"
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Nov 10 2005, 08:58 AM
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#6
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![]() Member ![]() ![]() ![]() ![]() Group: Full Member Posts: 165 Joined: 3-September 04 Member No.: 861 |
Thanks ralph,
The downstream equipment is protected my individual MCB's and the Feeders are protected by MCCB's. The earthing is solid grounded.and we are using SEPAm 1000 ( Schneider electric ) protectivve system. For a typical load of 6mva on a 15mva x-mer what should be the OC settings and Ef settings. Currently OC is (1A) at set for SIT curve and 330 amps and 300msec delay, and (1B) definite at 9.9ka EF is (1A)definite 40 Amps with delay of 100msec. and (1B) is 9ka with 300ms delay. hope this info will be of help. thanks again chaterpilar |
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Nov 10 2005, 12:41 PM
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#7
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Intermediate Member ![]() ![]() ![]() Group: Members Posts: 30 Joined: 8-November 02 From: Northern Cape, South Africa Member No.: 168 |
chaterpillar:
You have to have coordination between your relays downstream, the transformer relay, and the relays upstream. You do not want your main breaker to trip for a fault at a downstream motor's terminals. Therefore you have to do a coordination study to ensure that your downstream relays will trip before your upstream relays. That is called protective coordination. Thus, you have to set the transformer's secondary feeder on such a way that it does not trip before a downstream relay. If the downstream relay do not clear the fault for any reason, then the upstream relay has to operate. Now for the relay curves: You can use either a direct time or a IDMTL-curve (Inverse definite minimum time lag) For a direct time: your relay will operate in the set time if the set current is exceeded. For the IDMT-curves: The bigger the current into a relay, the faster will the relay operate. There are a lot of curves in use, but the most common are: IEC-world: standard/normal inverse very inverse extremely inverse long-time inverse short-time inverse ANSI/IEEE-world Moderately inverse inverse very inverse extremely inverse short-time inverse etc. The IEC and ANSI-curves are not the same, but uses the same principle. These curves have two setpoints: Current and Time Note that it is not a specific time, but a time-multiplier. The triptime of a relay would be dependant on the current factor (fault-current/set-current) and the time multiplier. Download the NPAG-Book at Areva's site (free download) and read especially through chapter 9 (Overcurrent and earth fault protection): http://www.areva-td.com/servlet/ContentSer...089880316992&am p;rid=&lid=en&pid=1017999014820&tab=Chapters&id=1056536208254 (copy and paste whole address) A few comments on some of your settings: For a infinite bus, your max. three phase short circuit current will be almost 7kA. Assuming you are using a standard/normal inverse curve from the IEC-world: Your O/C setting of 330A is almost 8MVA. That is where your relay will begin to pick-up. The time multiplier is set on 0.3 (not 300msec - it is a factor, not a time) For a fault of 7kA your relay will trip theoretically in 0.67sec For a fault of 1kA your relay will trip theoretically in 1.87sec Your O/C instantaneous element will never operate, because you will never see such a high current. For your earth-faults (remember with a solid earth your earth-fault currents can be very high) For any earth-fault above 40A your relay will operate in 0.1second due to the fact that you use a definite time setting Hope this will help you Regards Ralph |
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Nov 10 2005, 02:21 PM
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#8
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Intermediate Member ![]() ![]() ![]() Group: Members Posts: 30 Joined: 8-November 02 From: Northern Cape, South Africa Member No.: 168 |
Just an extra comment:
Overcurrent Protection is not the same as Overload Protection. There is a general misconception that an IDMT O/C relay is there and to be set to cover overloading of a transformer. If the thermal characteristic of a transformer is plotted against the normal inverse curve, (which is on log-log graph scale) it will be seen as a straight line crossing the IDMT characteristic at some point. For small overloads the relay will trip before the transformer heats up to its limit. For sudden heavy overloads the transformer will cook before the relay trips. The NI IDMT-relay is therefore NOT suitable for overload duty - it is for fault protection. Some degree of overload protection may be obtained with these curves. For overload monitoring of a transformer use: 1.) a relay with a suitable thermal characteristic. 2.) an EI characteristic in the IDMT range, the time being approx inverse proportional to the square of the current. 3.) Winding temp protection. |
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Nov 11 2005, 10:07 AM
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#9
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![]() Member ![]() ![]() ![]() ![]() Group: Full Member Posts: 165 Joined: 3-September 04 Member No.: 861 |
Ralph,
You have aanswered all my questions. thanks again. Chaterpilar " If you tell the truth, you don't have to remember your lies !" |
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Nov 11 2005, 10:07 AM
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#10
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![]() Member ![]() ![]() ![]() ![]() Group: Full Member Posts: 165 Joined: 3-September 04 Member No.: 861 |
Ralph,
You have answered all my questions. thanks again. Chaterpilar " If you tell the truth, you don't have to remember your lies !" |
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