IPB


Welcome Guest ( Log In | Register )

 
Reply to this topicStart new topic
Soft Starter Settings For Centrifugal Pump Application
Digg this topic · Save to del.icio.us · Slashdot It · Post to Technorati · Post to Furl · Submit to Reddit · Share on Facebook · Fark It · Googlize This Post · Add to ma.gnolia · Tag to Wink · Add to MyWeb · Add to Netscape
Leighc
post Dec 17 2007, 04:21 AM
Post #1


Junior Member
**

Group: Members
Posts: 4
Joined: 28-November 07
Member No.: 4,052



Hello everyone,

I've been reading this forum for some time trying to improve my knowledge base, thanks to everyone who posts answers, now I have a question of my own.

I have to set up a soft starter for a 30kW centrifugal pump. I have two options for the start curve, a flat current limit start with soft start turned off or the soft start curve that ramps the current up over time.

I'm trying to determine which type of start curve is best for a centrifugal pump with high resistive starting torque? Or how should I determine which start curve is best?

If I start the pump with a flat current limit start I imagine the pump will ramp up very rapidly after the initial resistance is overcome and if I start it with a current ramp I'm concerned I won't get the required starting torque.

Thanks, Leigh
Go to the top of the page
 
+Quote Post
marke
post Dec 18 2007, 08:52 AM
Post #2


Posting Freak
******

Group: Moderator
Posts: 2,088
Joined: 24-April 02
From: Christchurch, New Zealand
Member No.: 1



Hello Leighc

Welcome to the forum.

In order to answer your question, it is important that you understand the speed torque curve of the pump and the motor and also the current speed curve of the motor.

The pump torque curve basically increases with the square of the speed.

Create the speed torque curve of the pump.
On this curve, add the full voltage start torque of the motor.
Next you can plot a series of start torque curves for the motor under a constant current start.
Each point on the curve can be calculated by multiplying the full voltage start torque at that speed by the square of the current reduction at that speed.
From these curves, you can determine the minimum start current (if the start torque curve crosses the load torque, the pump can not start) and you can also determine the relative acceleration. (gap between the curves is the acceleration torque.)

A current ramp will boost the current and therefore the torque with time.

The advantage of the current ramp, is that you can start with a lower start current and the current will ramp up to the value required to develop enough torque to start the pump. The disadvantage is that the torque towards the end of the start is higher.

Best regards,


--------------------
Go to the top of the page
 
+Quote Post
Leighc
post Jan 7 2008, 03:40 AM
Post #3


Junior Member
**

Group: Members
Posts: 4
Joined: 28-November 07
Member No.: 4,052



Thanks for your help marke, I see how it works.

Best regards, Leighc

QUOTE (marke @ Dec 18 2007, 07:52 PM) *
Hello Leighc

Welcome to the forum.

In order to answer your question, it is important that you understand the speed torque curve of the pump and the motor and also the current speed curve of the motor.

The pump torque curve basically increases with the square of the speed.

Create the speed torque curve of the pump.
On this curve, add the full voltage start torque of the motor.
Next you can plot a series of start torque curves for the motor under a constant current start.
Each point on the curve can be calculated by multiplying the full voltage start torque at that speed by the square of the current reduction at that speed.
From these curves, you can determine the minimum start current (if the start torque curve crosses the load torque, the pump can not start) and you can also determine the relative acceleration. (gap between the curves is the acceleration torque.)

A current ramp will boost the current and therefore the torque with time.

The advantage of the current ramp, is that you can start with a lower start current and the current will ramp up to the value required to develop enough torque to start the pump. The disadvantage is that the torque towards the end of the start is higher.

Best regards,

Go to the top of the page
 
+Quote Post

Reply to this topicStart new topic
1 User(s) are reading this topic (1 Guests and 0 Anonymous Users)
0 Members:

 



Collapse

> Similar Topics

    Topic Title Replies Topic Starter Views Last Action
No new   32 marke 13,321 28th March 2008 - 01:02 PM
Last post by: lau
No New Posts   5 uhaykir 2,279 5th July 2002 - 09:08 AM
Last post by: marke
No New Posts   3 marke 2,507 24th January 2003 - 07:05 PM
Last post by: marke
No New Posts   1 marke 2,257 14th July 2003 - 12:44 AM
Last post by: GGOSS
No New Posts   3 -Ravisankar- 1,987 28th June 2002 - 08:04 AM
Last post by: GGOSS



RSS Lo-Fi Version Time is now: 15th October 2008 - 11:59 PM
hosted by : L M Photonics Ltd