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broc028
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Joined: 1-May 09
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Last Seen: 1st May 2009 - 03:42 PM
Local Time: Mar 12 2010, 11:40 PM
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1 May 2009
I am starting out on a project to look at possible savings from replacing some oversized motors.
Motor Input kW has been calculated from: kW=(Volts x Amps x 1.73 x P.F.)/1000 Motor Load has been calculated from: Load=kW/(Rated HP x 0.746) All values are measured.If I have a 10 H.P. motor running at 50% load, how do I justify replacing it with a 5 H.P. motor. |
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Lo-Fi Version | Time is now: 12th March 2010 - 11:40 PM |
