Rzn Posted October 13, 2006 Report Share Posted October 13, 2006 Dear All, We have a vacuum blower working at a corrugated machine. It has an eddy current motor 400vac, 50HZ, 15KW and 1390RPM. Vcc blower is driven through V belts. The size of both pulleys is same. Now the life of vcc blower is over and we want to replace it. I want to increase the rpm of blower up to 20% by decreasing the size of its pulley. What is the formula for calculating the desired KW of motor? Someone told to me that this new application requires more than 50% more power of motor (22.5KW). Is it true? I want to know the proper formulas. Any help will be highly appreciated. Link to comment Share on other sites More sharing options...
jOmega Posted October 13, 2006 Report Share Posted October 13, 2006 The vacuumn blower is undoubtedly a centrifugal load type device. As such, POWER is proportional to the cube of the speed. In your case, you want to increase the speed by 20% : from 1390 rpm to 1688 rpm. Here's the math: 1688 ÷ 1390 = 1.2 1.2 ^3 = 1.728 15 kW x 1.728 = 26 kW A 30 kW motor should handle the additional power requirements without any concern. NB! Verify that the Eddy Current Coupling is rated for the additional speed and power transmission. jΩ Link to comment Share on other sites More sharing options...
Rzn Posted October 14, 2006 Author Report Share Posted October 14, 2006 Dear jOmega, Thanks for your useful information. I would apply and inform members in this forum for this kind of experience. Link to comment Share on other sites More sharing options...
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