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Power Factor Correction


AB2005

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Dear All,

 

We have a large number of Fluorescent and mercury lamps in our plant. I want to connect the PFC capacitor at each lamp for reducing the line losses. Please check my calculations for single phase capacitor and guide to me if you found any mistake.

 

QC=Px(tanΦ1-tanΦ2)

 

QC=V²xWxC

 

C=QC/V²xW

 

For example, Fluorescent lamp = 40W, 220V, 50HZ and cosΦ 0.45. I want to improve the power factor at 0.96. So,

 

QC=40x(1.98-0.29)

 

QC=67.6VAR

 

C=67.6/220x220x(2x3.14x50)

 

C=4.4uf

 

Is it correct?

 

 

 

 

 

"Don't assume any thing, always check/ask and clear yourself".

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