SAMER Posted November 12, 2005 Report Share Posted November 12, 2005 HiI would like exactly why the synchronous speed decrease when number of Poles increase and the demonstration of the below equation:Ns=120*f/p Link to comment Share on other sites More sharing options...
chaterpilar Posted November 13, 2005 Report Share Posted November 13, 2005 Dear samer, All loads moved by electric motors are really moved by magnetism. The purpose of every component in a motor is to help harness, control, and use magnetic force. When applying an AC drive system it helps to remember you are actually applying magnets to move a load. To move a load fast does not require more magnets, you just move the magnets fast. To move a heavier load or to decrease acceleration time (accelerate faster) more magnets (more torque) are needed. This is the basis for all motor applications. Now when you have less poles the interchange of magnets is fastest and hence the speed is more. hope it answers your question. Chaterpilar " If you tell the truth, you don't have to remember your lies ! " Link to comment Share on other sites More sharing options...
SAMER Posted November 15, 2005 Author Report Share Posted November 15, 2005 where is the demonstratin of the formula Ns=120*f/p? Link to comment Share on other sites More sharing options...
GGOSS Posted November 16, 2005 Report Share Posted November 16, 2005 Hello SAMER I would have thought that the information provided by chaterpilar (excellent work) would have been sufficient for you. As that does not appear to be the case, the following should help you further. Definitions:Ns = Synchronous speed120 = Engineering constantf = frequencyp = number of poles It is clear from the above, syncrounous speed is inversly proportional to number of poles. Take for example; 2 pole motor, 50Hz supplyNs = (120 x 50) / 2 = 3000 RPM 4 pole motor, 50Hz supplyNs = (120 x 50) / 4 = 1500 RPM Regards,GGOSS Link to comment Share on other sites More sharing options...
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